Saturday, December 5, 2009

Steady Heat Tech Deck Steady State Heat Flow?

Steady state heat flow? - steady heat tech deck

How do I calculate the amount of time it takes to steady-state heat flow in the following situation to achieve:

Heat is absorbed at a constant rate of 1.34 Cal / sec on the basis of an aluminum (1 "x 3" cylinder). The only place where the heat lost to the top of the bottle (east side only). Thermal conductivity of aluminum is 49 cal / (sec x cm x º C)

* Simple and brief explanation as possible, please

1 comment:

mariskalen kampf Strudl v.Wurst! said...

This could be represented by an exponential function

e ^ (T / T)

where T is the time constant,

Thermal_resistance T = x = R x C thermal_capacitance

R = cyl_length / thermal_cond x cyl_surface

C = specific_heat x cyl_mass

(at) spec_heat = 0215 cal / g º C

and can be taken.

Perform a dimensional inspection.
.

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